In Regexes§

See primary documentation in context for Lexical conventions 0

Substitutions are written similarly to matching, but the substitution operator has both an area for the regex to match, and the text to substitute:

s/replace/with/;           # a substitution that is applied to $_ 
$str ~~ s/replace/with/;   # a substitution applied to a scalar 

The substitution operator allows delimiters other than the slash:

s|replace|with|;
s!replace!with!;
s,replace,with,;

Note that neither the colon : nor balancing delimiters such as {} or () can be substitution delimiters. Colons clash with adverbs such as s:i/Foo/bar/ and the other delimiters are used for other purposes.

If you use balancing curly braces, square brackets, or parentheses, the substitution works like this instead:

s[replace] = 'with';

The right-hand side is now a (not quoted) Raku expression, in which $/ is available as the current match:

$_ = 'some 11 words 21';
s:g[ \d+ ] =  2 * $/;
.say;                    # OUTPUT: «some 22 words 42␤»

Like the m// operator, whitespace is ignored in the regex part of a substitution.